From: "Aleksey E. Birukov" <birukov@vladinfo.ru>
To: ledest@gmail.com,
ALT Linux sysadmin discuss <sysadmins@lists.altlinux.org>
Subject: Re: [Sysadmins] awk
Date: Wed, 30 Jul 2008 11:16:41 +0400
Message-ID: <48901559.5060807@vladinfo.ru> (raw)
In-Reply-To: <200807292357.44050.ledest@gmail.com>
Led пишет:
> Tuesday, 29 July 2008 23:11:12 Sergey Shilov написав:
>
>> В сообщении от Tuesday 29 July 2008 14:25:55 Aleksey E. Birukov написал(а):
>>
>>> Как вывести определенное поле в awk понятно {print($1)}. А вот как
>>> вывести сам текст-разделитель,
>>>
>> echo "aaa_bbb_ccc" | gawk 'FS = "_" { print FS }'
>>
>> из man gawk
>> FS variable as the field separator. If FS is a single character,
>> fields are separated by that character. If FS is the null string, then
>> each individual character becomes a separate field. Otherwise, FS is
>> expected to be a full regular expression.
>> Оно?
>>
>
> Врядли. Я так понял, хотелось получить конкретный номерной match в случае
> когда FS - regexp
>
Да. Именно так.
next prev parent reply other threads:[~2008-07-30 7:16 UTC|newest]
Thread overview: 12+ messages / expand[flat|nested] mbox.gz Atom feed top
2008-07-29 11:25 Aleksey E. Birukov
2008-07-29 20:11 ` Sergey Shilov
2008-07-29 20:57 ` Led
2008-07-30 7:16 ` Aleksey E. Birukov [this message]
2008-07-30 9:41 ` Sergey Shilov
2008-07-30 10:27 ` Led
2008-07-30 15:03 ` Шилов Сергей
2008-07-30 16:58 ` Aleksey E. Birukov
2008-07-30 17:17 ` Alexey Borisenkov
2008-07-30 20:10 ` Sergey Shilov
2008-07-30 18:12 ` Led
2008-07-30 20:51 ` Sergey Shilov
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