From: Led <ledest@gmail.com>
To: ALT Linux sysadmin discuss <sysadmins@lists.altlinux.org>
Subject: Re: [Sysadmins] awk
Date: Tue, 29 Jul 2008 23:57:44 +0300
Message-ID: <200807292357.44050.ledest@gmail.com> (raw)
In-Reply-To: <200807292311.13073.hsvhome@mail.ru>
Tuesday, 29 July 2008 23:11:12 Sergey Shilov написав:
> В сообщении от Tuesday 29 July 2008 14:25:55 Aleksey E. Birukov написал(а):
> > Как вывести определенное поле в awk понятно {print($1)}. А вот как
> > вывести сам текст-разделитель,
>
> echo "aaa_bbb_ccc" | gawk 'FS = "_" { print FS }'
>
> из man gawk
> FS variable as the field separator. If FS is a single character,
> fields are separated by that character. If FS is the null string, then
> each individual character becomes a separate field. Otherwise, FS is
> expected to be a full regular expression.
> Оно?
Врядли. Я так понял, хотелось получить конкретный номерной match в случае
когда FS - regexp
--
Led
next prev parent reply other threads:[~2008-07-29 20:57 UTC|newest]
Thread overview: 12+ messages / expand[flat|nested] mbox.gz Atom feed top
2008-07-29 11:25 Aleksey E. Birukov
2008-07-29 20:11 ` Sergey Shilov
2008-07-29 20:57 ` Led [this message]
2008-07-30 7:16 ` Aleksey E. Birukov
2008-07-30 9:41 ` Sergey Shilov
2008-07-30 10:27 ` Led
2008-07-30 15:03 ` Шилов Сергей
2008-07-30 16:58 ` Aleksey E. Birukov
2008-07-30 17:17 ` Alexey Borisenkov
2008-07-30 20:10 ` Sergey Shilov
2008-07-30 18:12 ` Led
2008-07-30 20:51 ` Sergey Shilov
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