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From: Yuriy Kashirin <yura@emict.com>
To: ALT Linux Sisyphus discussion list <sisyphus@lists.altlinux.org>
Subject: Re: [sisyphus] zsh/bash: подстановка значений в строку
Date: Wed, 18 Jul 2007 12:44:00 +0300
Message-ID: <200707181244.01684.yura@emict.com> (raw)
In-Reply-To: <75e139a00707180158v7517a97i439a40da3943deee@mail.gmail.com>

On Среда 18 июля 2007, Slava Semushin wrote:
> Здравствуйте!
>
> [c0der@rock ~]$ cat example
> FOO = bar
>
> [c0der@rock ~]$ /bin/bash -c 'FROM=FOO;TO=test;sed
> "s|$FROM[[:space:]]*=.*|$FROM=$TO|" example| diff -u example -'
> --- example     2007-07-18 15:51:27 +0700
> +++ -   2007-07-18 15:55:33 +0700
> @@ -1 +1 @@
> -FOO = bar
> +FOO=test
>
> [c1der@rock ~]$ /bin/zsh -c 'FROM=FOO;TO=test;sed
> "s|$FROM[[:space:]]*=.*|$FROM=$TO|" example| diff -u example -'
> zsh: bad output format specification
> [c1der@rock ~]$
>
> Почему в zsh это не работает?

zsh пытатется раскрыть $FROM с учетом того, что находится сразу после 
имени переменной в квадратных скобках (man zshparam на предмет Array 
Subscripts, насколько я понимаю).

> И можно ли как-нибудь сделать, чтобы 
> работало в обоих шеллах?

Попробовать вместо $FROM[[:space:]] написать ${FROM}[[:space:]]

>
> Спасибо заранее.



-- 
 Best regards
 Yuriy Kashirin

      reply	other threads:[~2007-07-18  9:44 UTC|newest]

Thread overview: 2+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2007-07-18  8:58 Slava Semushin
2007-07-18  9:44 ` Yuriy Kashirin [this message]

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