From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: X-Spam-Checker-Version: SpamAssassin 3.2.3 (2007-08-08) on sa.int.altlinux.org X-Spam-Level: X-Spam-Status: No, score=-0.8 required=5.0 tests=AWL,BAYES_00 autolearn=ham version=3.2.3 X-Virus-Scanned: amavisd-new at telenet.dn.ua Date: Fri, 02 May 2008 18:56:50 +0300 To: "ALT Linux Community general discussions" From: "Aleksander N.Gorohovski" Content-Type: text/plain; format=flowed; delsp=yes; charset=koi8-r MIME-Version: 1.0 References: <200805021934.40758.haw@inbox.ru> Content-Transfer-Encoding: 8bit Message-ID: In-Reply-To: <200805021934.40758.haw@inbox.ru> User-Agent: Opera Mail/9.25 (Linux) Subject: Re: [Comm] =?koi8-r?b?+sHQ1dPLIG5mcw==?= X-BeenThere: community@lists.altlinux.org X-Mailman-Version: 2.1.10b3 Precedence: list Reply-To: ALT Linux Community general discussions List-Id: ALT Linux Community general discussions List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , X-List-Received-Date: Fri, 02 May 2008 15:56:53 -0000 Archived-At: List-Archive: List-Post: On Fri, 02 May 2008 18:34:40 +0300, Владимир wrote: > http://haw.hut2.ru/index.html Интересно, А что означает ссылка "Формулы"? У меня отображается какая то каша amath Solving the quadratic equation. Suppose a x^2+b x+c=0 and a!=0. We first divide by \a to get x^2+b/a x+c/a=0. Then we complete the square and obtain x^2+b/a x+(b/(2a))^2-(b/(2a))^2+c/a=0. The first three terms factor to give (x+b/(2a))^2=(b^2)/(4a^2)-c/a. Now we take square roots on both sides and get x+b/(2a)=+-sqrt((b^2)/(4a^2)-c/a). Finally we subtract b/(2a) from both sides and simplify to get the two solutions: x_(1,2)=(-b+-sqrt(b^2 - 4a c))/(2a) endamath