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Date: Fri, 07 Jul 2006 19:23:27 +0300
From: Olvin <olvin@rambler.ru>
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Вот такая програмка (файл test.c):

#include <fcntl.h>
int main (int argc, char *argv[]) {
  int fd,tmp,a;
  struct stat *buf;
  void *fb;
  fd = open("/tmp/tst",O_RDONLY);
  tmp = fstat(fd,buf);
}

Компиляция:

$ cc -o test test.c

Запуск:

$ touch /tmp/tst
$ ./test
Segmentation fault
$

Но стоит изменить int fd,tmp,a на int fd,tmp и уже не сегфолтится. 
Однако при попытке распечатать с помощью того же printf значение tmp - 
снова сегфолт.

В чём дело?

$ cc --version
2.96
$ uname -a
Linux olvin.enigma.local 2.4.26-std-up-alt13 #1 Mon Nov 14 00:25:14 MSK 
2005 i686 unknown unknown GNU/Linux

ALM2.4.