From: "Kirill A. Shutemov" <kirill@shutemov.name> To: ALT Linux Team development discussions <devel@lists.altlinux.org> Cc: Michail Yakushin <silicium@altlinux.org>, "Konstantin A. Lepikhov" <lakostis@unsafe.ru>, "Dmitry V. Levin" <ldv@altlinux.org> Subject: [devel] suid binaries and ELF Auxiliary Vectors Date: Fri, 25 Sep 2009 10:38:50 +0300 Message-ID: <cc557aab0909250038l20f2cdc3v9f89234b1732b2c@mail.gmail.com> (raw) Может кто-нибудь подскажет, почему suid'ый бинарник получает пустой auxv? Маленький testcase: #include <elf.h> #include <stdio.h> #include <unistd.h> int main(int argc, char **argv, char **envp) { Elf32_auxv_t *auxv; while(*envp++ != NULL); for (auxv = (Elf32_auxv_t *)envp; auxv->a_type != AT_NULL; auxv++) printf("%d: 0x%08x\n", auxv->a_type, auxv->a_un.a_val); printf("uid: %d\n", geteuid()); return 0; } Для x86_64, его нужно немного поправить. Если у исполняемого файла нет suid-бита(или owner == uid), то auxv печатается нормально иначе получаем только uid. Есть идеи почему? И где код кторый это делает? Немного о себе: $ uname -r 2.6.30-lks-wks-alt1 $ rpm -q glibc-core glibc-core-2.10.1-alt6
next reply other threads:[~2009-09-25 7:38 UTC|newest] Thread overview: 9+ messages / expand[flat|nested] mbox.gz Atom feed top 2009-09-25 7:38 Kirill A. Shutemov [this message] 2009-09-25 8:15 ` Kirill A. Shutemov 2009-09-25 8:23 ` Kirill A. Shutemov 2009-09-25 9:12 ` Dmitry V. Levin 2009-09-25 9:24 ` Sergey Vlasov 2009-09-25 10:05 ` Kirill A. Shutemov 2009-09-25 10:20 ` Kirill A. Shutemov 2009-09-25 9:29 ` Andrey Rahmatullin 2009-09-25 9:35 ` Dmitry V. Levin
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