Re: [Comm] Запуск nfs

["Aleksander N.Gorohovski" <angel@feht.dgtu.donetsk.ua>]

On Fri, 02 May 2008 18:34:40 +0300, Владимир wrote:

> http://haw.hut2.ru/index.html

Интересно,
А что означает ссылка "Формулы"?

У меня отображается какая то каша

amath Solving the quadratic equation. Suppose a x^2+b x+c=0 and a!=0. We  
first divide by \a to get x^2+b/a x+c/a=0. Then we complete the square and  
obtain x^2+b/a x+(b/(2a))^2-(b/(2a))^2+c/a=0. The first three terms factor  
to give (x+b/(2a))^2=(b^2)/(4a^2)-c/a. Now we take square roots on both  
sides and get x+b/(2a)=+-sqrt((b^2)/(4a^2)-c/a). Finally we subtract  
b/(2a) from both sides and simplify to get the two solutions:  
x_(1,2)=(-b+-sqrt(b^2 - 4a c))/(2a)
endamath